Question

if xyz=8 and 1/x+1/y+1/z=2/3 then the value of xy+yz+zx​

Answer 1

Answer:

$\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{yz + xz + xy}{xyz} = \frac{2}{3} \\ = \frac{xy + yz + zx}{8} = \frac{2}{3} = xy + yz + zx \\ = \frac{16}{3}$