Question

if xyz are three integers such that x+y=8, y+x=13 and z+x=17 then the value of x²/y^z​

Answer 1

Step-by-step explanation:

x+y=8—(1)

x+z=13—(2)

z-w=6—(3)

w+y=8—(4)

Subtracting eqn 1 from eqn 2 we get,

x+z-x-y=13–8

z-y=5—(5)

Adding eqn 3 and eqn 4 we get,

z-w+w+y=6+8

z+y=14—(6)

Adding eqn 5 and eqn 6 we get,

z-y+z+y=5+14

2z=19

z=9.5

Putting this in eqn 6 we get

9.5+y=14

y=4.5

Putting this in eqn 1 we get,

x+4.5=8

x=3.5

Putting y in eqn 4 we get,

w+4.5=8

w=3.5

Answer 2

Answer:

hope it's helpful to you!

Step-by-step explanation:

Given,

x+y=8, y+z=13 and z+x=17

x^2/yz=?

y+z-(x+y)=13–8

=>z-x=5

Again

z-x+z+x=5+17

=>2z=22

=>z=11

Putting z in z+x and y+z we get

11+x=17 y+11=13

x=6 and y=2

Therefore, x^2/yz=36/11*2

x^2/yz=18/11