if y=0.02sin(x/0.01+t/0.05) where y is in metres, find the amplitude of wave, wavelength, frequency, wave velocity and initial phase at origin
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Answer:
The equation of given transverse wave is y=0.05sinπ(2t−0.02x) .......(1)
On comparing (1) with y=Asin(wt−kx)
We get, k=0.02π and w=2π
Wave velocity v=
k
w
=
0.02π
2π
=100 m/s
Minimum distance of separation between two particles which are in phase is equal to the wavelength of the wave.
Wavelength λ=
k
2π
=
0.02π
2π
=100 m
Explanation:
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