If y-1, 3y-1, 2y are in AP then value of y is
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Answer:
1/3 is the answer
Step-by-step explanation:
since y-1,3y-1,2y are in AP
therefore it will be
2b=a+b
therefore
2(3y-1)=y-1+2y
6y-2=3y-1
3y=1
y=1/3
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