Math, asked by kriti7784, 11 months ago

If y-1, 3y-1, 2y are in AP then value of y is

Answers

Answered by manduvajayasree
5

Answer:

1/3 is the answer

Step-by-step explanation:

since y-1,3y-1,2y are in AP

therefore it will be

2b=a+b

therefore

2(3y-1)=y-1+2y

6y-2=3y-1

3y=1

y=1/3

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