Math, asked by 1386, 8 months ago

If y=1+5^1/3+5^2/3, then find the value of y^3-3y^2-12y+6.

Answers

Answered by ssukhpuri
0

Step-by-step explanation:

y=1+5^1/3+5^2/3

1+5/3+25/3

1+5/28/3

1+15/28

=16/28

=4/7

the value of y is =4/7

put in value ,y =4/7

4/7^3-3×4/7^2-12×4/7+6

64/343-4849-48/7+6

-569/343

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