Question

if y=1/√a^2-x^2,find dy/dx​

Answer 1

hope this will help you...........

Answer 2

Answer:

answer

Step-by-step explanation:

Putting (a2−x2)=t, we get

y=1t√=t−1/2andt=(a2−x2)

⇒ dydx=−12t−3/2=−12t3/2anddtdx=−2x

⇒ dydx=(dydt×dtdx)=−12t3/2×(−2x)=x(a2−m2)3/2