Question

if y =1 is a common root of the equation ay^2+ay+3=0 and y^2+y+b=0, then what will be the value of ab​

Answer 1

Answer:

ab=3

Step-by-step explanation:

It is given in the pic.

Answer 2

Answer:3

Step-by-step explanation:

placing value of y in first equation we get a(1)^2+a(1)+3=0

then a+a +3=0

2a =-3

a=-3/2

putting value of y in second equation we get (1)^2+1+b=0

2+b=0

b=-2

then ab=-3/2*-2=3