Question

if y=-1 is a zero of. q(y)=4y3+ky2-y-1 then find the value of k
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Answer 1

Step-by-step explanation:

Given that :

y=-1 is the zero of q(y)

Put the value of y in the equation.

q(-1)= 4(-1)(3)+k(-1)(2)-(-1)-1=0

= -12-2k+1-1=0

= -12-2k=0

-2k=12

k=12/-2

k=-6

Answer 2

Answer

k = 4

Step-by-step explanation:

It is given that y = -1 is a zero of the polynomial,

so q(-1) = 4y^3+ky^2-y-1 = 0

4(-1)^3 + k(-1)^2 - (-1) -1 = 0

-4 + k + 1 -1 = 0

k - 4 = 0

k = 4