If y=-1 is a zero of the polynomial q (y) = 4y^3 + ky^2- y -1, then find the value of k
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1
Answer:
k = 4
Step-by-step explanation:
Since y=-1 is a zero we can substitute it and equate to zero as
4(-1)^3+k(-1)^2-(-1)-1 =0
4(-1) +k +1 -1 = 0
-4 +k =0
k =4
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answer for the given problem is given
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