Question

If (y-1) is the factor of the polynomial y3-2y2+my+4 then find the value of m
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Answer 1

Answer:

$y - 1 = 0 \\ y = 1 \\ \\ {y}^{3} - 2 {y}^{2} + my + 4 = 0 \\ \\ {1}^{3} - 2( {1})^{2} + m(1) + 4 = 0 \\ \\ 1 - 2 + m + 4 = 0 \\ \\ 3 + m = 0 \\ \\ m = - 3$

Answer 2

Step-by-step explanation:

y−1=0

y=1

y

3

−2y

2

+my+4=0

1

3

−2(1)

2

+m(1)+4=0

1−2+m+4=0

3+m=0

m=−3

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