if y= ( 1-sec2x ) &(4+5sin2x) then find the value of dx/dy =
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The derivative of sec(x) is sec(x)tan(x)sec(x) is sec(x)tan(x), with x in radians. Since you asked for degrees, lets write sec(x) with x in radians as
sec(π180x)sec(π180x). The derivative of this (in radians) is π180sec(π180x)tan(π180x)π180sec(π180x)tan(π180x).
Converting back to degrees gives π180sec(x)tan(x)
sec(π180x)sec(π180x). The derivative of this (in radians) is π180sec(π180x)tan(π180x)π180sec(π180x)tan(π180x).
Converting back to degrees gives π180sec(x)tan(x)
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if y= ( 1-sec2x ) &(4+5sin2x) then find the value of dx/dy = .. what is the answer
if y= ( 1-sec2x ) &(4+5sin2x) then find the value of dx/dy =
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