If y= 1+x/1!+x^2/2!+x^3/3!,
Prove that dy/dx=y
Answers
Answer:
Please see the attachment
Step-by-step explanation:
We know that,
eˣ = 1 + x/1! + x²/2! + x³/3! + x⁴/4! + ... ∞
Let, y = eˣ (as given)
Now differentiating both sides with respect to x, we get
dy/dx = d/dx (eˣ)
= eˣ
= y, as considered
Thus dy/dx = y. Hence proved.
Rules:
• d/dx (eᵐˣ) = m eᵐˣ, m is a rational number
• d/dx (xᵐ) = m xᵐ⁻¹, m is an integer
Note: However we can proceed by taking derivatives of the terms of x and we will get y again, as given. Thus we can prove dy/dx = y.
Similar type of problems:
1. Differentiate Sin inverse of 2 X upon oneplus x square with respect to Cos inverse of 1 - x square upon oneplus x square - https://brainly.in/question/3911961
2. solve (x+y-2)dx+(x-y+4)dy=0 - https://brainly.in/question/3012078