Question

If y=(1-x)(2x+3) find the value of X when y =0,2 and -3

Answer 1

Answer:

y=0

0=(1-x)(2x+3)

0=2x+3-2x^2-3x

0=-2x^2-x+3---------------------(1)

2x^2+x-3=0

2x^2+3x-2x-3

x(2x+3)-1(2x+3)

(x-1)(2x+3). [X=1,-3/2]

y=2

2=-2x^2-x+3---------(from 1)

-2x^2-x+1=0

2x^2+x-1=0

2x^2+2x-x-1=0

2x(x+1)-1(x+1)

(2x-1)(x+1) [x=1/2,-1]

y=-3

-3=-2x^2-x+3------------(from1)

-2x^2-x+6=0

-2x^2-4x+3x+6=0

-2x(x+2)+3(x+2)

(x+2)(-2x+3) [x=-2,3/2]

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