If y=1+x+x^2+x^3+.... Infinite so prove x=1-1/y
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Solution:
We have to prove,
x = 1 - (1/y)
y = 1 + x + x² + x³ + - - - - ∞
Given series is in geometric progression.
Therefore,
r = common ratio
r = {Tn/(Tn-1)}
r = x/1
r = x
Note: a (first term of series) = 1
The formula for finding infinite sum in geometric series is:
S∞ = a/(1-r)
Hence,
S∞ = 1 / (1-x) = y
(1- x) = 1/y
-x =(1/y) - 1
Taking (-1) on both the sides:
x = -(1/y)+1
x = 1-(1/y)
Hence proved.
_________________
Answered by: Niki Swar, Goa❤️
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