If (Y-1), (Y+1) and (2Y+3) are in A.P. , then value of 'Y' is Please answer fast
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Step-by-step explanation:
If three numbers a,b,c are in AP, then
b - a = c - b
so, here
(y + 1) - (y - 1) = (2y + 3) - (y + 1)
y + 1 - y +1 = 2y + 3 - y - 1
2 = y + 2
y = 2 - 2
y = 0
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