if y+1/y=12 then y(cube)+1/y(cube) is equal to what
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y+1/y=12
then use formula
(y+1/y) ³=y³+1/y³+3y×1/y(y+1/y)
put the above value
12³= y³+1/y³+ 3(12)
12³-12×3=y³+1/y³
12(12²-3) = y³+1/y³
12×141= y³+1/y³
1410+282=y³+1/y³
1692 = y³+1/y³ answer please mark as Brainlist if you happy with my answer. Thanks
then use formula
(y+1/y) ³=y³+1/y³+3y×1/y(y+1/y)
put the above value
12³= y³+1/y³+ 3(12)
12³-12×3=y³+1/y³
12(12²-3) = y³+1/y³
12×141= y³+1/y³
1410+282=y³+1/y³
1692 = y³+1/y³ answer please mark as Brainlist if you happy with my answer. Thanks
ymy34513:
you are very much thankyou
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