Question

if y-1/y=3+2√2,then find the value of y3-1/y3​

Answer 1

Answer:

Step-by-step explanation:

$y-\frac{1}{y}=3+2\sqrt{2}$

squaring both the sides

$(y-\frac{1}{y})^{2}=y^{2}+\frac{1}{y^{2}}-2\\\\(3+2\sqrt{2})^{2}+2=y^{2}+\frac{1}{y^{2}}\\\\9+8+4\sqrt{2}+2=y^{2}+\frac{1}{y^{2}}\\\\19+4\sqrt{2}=y^{2}+\frac{1}{y^{2}}$

$y^{3}-\frac{1}{y^{3}}=(y-\frac{1}{y})(y^{2}+\frac{1}{y^{2}}+(y)(\frac{1}{y})\\\\y^{3}-\frac{1}{y^{3}}=(3+2\sqrt{2})(19+4\sqrt{2}+1)\\\\y^{3}-\frac{1}{y^{3}}=60+12\sqrt{2}+40\sqrt{2}+16\\\\y^{3}-\frac{1}{y^{3}}=76+52\sqrt{2}$

I hope this helps

Answer 2

Step-by-step explanation:

माइनस वन अपऑन बाय इज इक्वल टू टू टू टू टू टू फाइंड द वैल्यू ऑफ ऑल की पावर 3 माइनस वन अपऑन मंत्री