If y=10^logx / x^2 and x=y^A then A=
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Answered by
12
Answer:
Here, I assume that the base of log is 10. So, it is given that 10=log10x . By defn. of log, then, we have, x=1010
Answered by
19
Answer:
A = -1
Step-by-step explanation:
Given, y=10^logx base 10/x^2
y=x^log10 base 10/x^2
=x^1/x^2
y=1/x
=x^-1
x^A=x^-1
A= -1
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