Question

If y=(10^logx)/(x) and x=y^A then A=?​

Answer 1

Answer:

Given,

y=log

10

x+log

x

10+log

x

x+log

10

10

⇒y=log

10

e⋅log

e

x+

log

e

x

log

e

10

+1+1

On differentiating with respect to x, we get

dx

dy

=

x

1

log

10

e−

x(log

e

x)

2

log

e

10

=

xlog

e

10

1

−

x(log

e

x)

2

log

e

10