If y=(10^logx)/(x) and x=y^A then A=?
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Answer:
Given,
y=log
10
x+log
x
10+log
x
x+log
10
10
⇒y=log
10
e⋅log
e
x+
log
e
x
log
e
10
+1+1
On differentiating with respect to x, we get
dx
dy
=
x
1
log
10
e−
x(log
e
x)
2
log
e
10
=
xlog
e
10
1
−
x(log
e
x)
2
log
e
10
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