If y = 12 and xy = 27. then find the value of x cube and y cube
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xy = 27
y = 12
x = 27 / 12
x = 9 / 4
x^3 = 729 / 64
y^3 = 1728
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answer:
(x+y)^3=x^3+3x^2y+3xy^2+y^3
= x^3+y^3+3xy(x+y)
x^3+y^3=(x+y)^3-3xy(x+y)
= (12)^3-3(27)(12)
=1728-972
x^3+y^3=756
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