Question

If y = 1f(x) is the solution of the differential equation dy/dx = (tanx - y)sec²x,
x ∈(-π/2, π/2)such that y(0) = 0, then y(-π/4) is equal to
(A) (1/2) - e
(B) (1/e) - 2
(C) e – 2 (D) 2 + (1/e)

Answer 1

Step-by-step explanation:

If y = 1f(x) is the solution of the differential equation dy/dx = (tanx - y)sec²x,

x ∈(-π/2, π/2)such that y(0) = 0, then y(-π/4) is equal to

(A) (1/2) - e

(B) (1/e) - 2

(C) e – 2✓✓✓

(D) 2 + (1/e)

Answer 2

Answer:

hey mate....

option A is the correct answer.............