if y=1is a common root of the equation ay^2+ay +3=0and y^2+y+b=0then ab equal to
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Answer:
ab = 3
Step-by-step explanation:
f(y) = ay²+ay+3
putting y =1 in the equation
f(1) = a(1)²+ a(1) + 3 = 0
a + a +3 =0
2a = -3
a = -3/2
similarly,
f(y) = y²+y+b
f(1) = 1² + 1 + b = 0
2 + b = 0
b = -2
so,
ab = (-3/2) × (-2)
ab = 3
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