Math, asked by ntsuvigya, 1 month ago

if y^2+1/y^2 =11 find th value of y-1/y​

Answers

Answered by astha1917
0

( \frac{ {y}^{2}  + 1}{ {y}^{2} } ) = 11

 {y}^{2}  + 1 = 11 {y}^{2}

1 = 11 {y}^{2}  -  {y}^{2}

1 = 10 {y}^{2}

 {y}^{2}  =  \frac{1}{10}

y =  \sqrt{ \frac{1}{10} }

y = 0.1

putting value of y in the given equation,

  •  \frac{y - 1}{y}
  •  \frac{0.1 - 1}{0.1}
  •  -9
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