If y =√+2 +√−2 / √+2− √−2, prove that b^2 – ay + b = 0
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As we know that
(a+b)2=a2+b2+2ab,(a−b)2=a2+b2−2ab
Given (x2+y2)(a2+b2)=(ax+by)2
x2(a2+b2)+y2(a2+b2)=(ax)2+(by)2+2(ax)(by)
⟹a2x2+b2x2+a2y2+b2y2=a2x2+b2y2+2abxy
⟹b2x2+a2y2=2abxy
⟹(bx)2+
Answered by
0
Step-by-step explanation:
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