Question

if y=2^2x then dy/dx=​

Answer 1

Answer:

$2^{2x+1}$㏒2

Step-by-step explanation:

$y = 2^{2x} \\\\logy=2xlog2\\\\\frac{1}{y} \frac{dy}{dx} =2log2\\\\\frac{dy}{dx}=y*2log2\\\\\frac{dy}{dx}=2log2*2^{2x} =2^{2x+1} log2$

Thanks.