Question

If y= 2/3 is a solution of the equation 7y² +ay- 3 = 0 then the value of a is​

Answer 1

Answer:

$a = - \frac{1}{6}$

Step-by-step explanation:

Putting value of y=2/3 in the equation:

$7 {y}^{2} + ay - 3 = 0$

$7 {( \frac{2}{3} )}^{2} + a( \frac{2}{3} ) - 3 = 0$

$\frac{7 \times 4}{9} + \frac{2a}{3} = 3$

$\frac{28 + 6a}{9} = 3$

$28 + 6a = 9 \times 3 \\ 28 + 6a = 27 \: \: \: \: \: \:$

$6a = 27 - 28 \\ 6a = - 1 \: \: \: \: \: \: \: \: \:$

$a = \frac{ - 1}{6}$

Answer 2

Answer:

\begin{gathered}a = - \frac{1}{6} \\ \end{gathered}

a=−

6

1

Step-by-step explanation:

Putting value of y=2/3 in the equation:

7 {y}^{2} + ay - 3 = 07y

2

+ay−3=0

\begin{gathered}7 {( \frac{2}{3} )}^{2} + a( \frac{2}{3} ) - 3 = 0 \\ \end{gathered}

7(

3

2

)

2

+a(

3

2

)−3=0

\begin{gathered} \frac{7 \times 4}{9} + \frac{2a}{3} = 3 \\ \end{gathered}

9

7×4

+

3

2a

=3

\begin{gathered} \frac{28 + 6a}{9} = 3 \\ \end{gathered}

9

28+6a

=3

\begin{gathered}28 + 6a = 9 \times 3 \\ 28 + 6a = 27 \: \: \: \: \: \: \end{gathered}

28+6a=9×3

28+6a=27

\begin{gathered}6a = 27 - 28 \\ 6a = - 1 \: \: \: \: \: \: \: \: \: \end{gathered}

6a=27−28

6a=−1

\begin{gathered}a = \frac{ - 1}{6} \\ \end{gathered}

a=

6

−1

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