Question

if y^2+7y+5p=0, thenthe integtral value of p for which the given equation doesnot have real roots can be ??

Answer 1

Answer:

Step-by-step explanation:

For no real roots Det should be less than zero Which is B^2 -4*A*C

So Here A is 1 and B is 7 and C is 5P

7^2 -4*1*5P should be less than zero

=49 -20P less than zero

=49/20 less than P

Which means P should be greater than 49/20