Question

if y-2 and 2y -1 are factors of ky^+5y+r then find value of k and r​

Answer 1

Answer:

Step-by-step explanation:

p(y)=ky^2+5y+r

y-2 and 2y-1 are factors of p(y) then

put y=2,1/2 in p(y)

p(2)=k(2^2)+5(2)+r=0

4k+10+r=0

4k+r+10=0-----(1)

p(1/2)=k(1/2)^2+5*(1/2)+r=0

k/4+5/2+r=0

k+10+4r=0---(2)

solve (1) and (2)

multiply (2) with 4

4k+r+10=0

4k+40+16r=0

-----------------

-15r-30=0

15r=-30

r=-2

substitute in (2)

k+10-8=0

k=-2

Answer 2

find the zero of polynomial of both then do equation 1-2 and find value of k and r