if y=2 and y=0 are zeros of polynomial h(y) =2y^3-5y^2+ay+b then find the value of (a^4-b^4)
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Answer:
b=0,a=2
Step-by-step explanation:
Using y=0 in equation yo find the value of b-
p(0)=2(0)^3-5(0)^2+a(0)+b
=0-0+0+b
therefore,b=0
now finding value of a by using y=2
p(2)=2(2)^3-5(2)^2+2a+0
=2(8)-5(4)+2a+0
=16-20+2a
=-4+2a
a=2
I hope my answer was helpful.....
thank you buddy for asking me this question.....
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