if y = 2 log sqft( 1 - cos x/ 1 + cos x) show that DY/DX equals to cosec x
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y= log(1-cos x/1+cos x)
y=log(1-cos x)-log(1+cos x)……..[by properties of logarithm log(a/b)=log a-logb]
Differentiating both sides we get,
dy/dx=[{1/(1-cos x)}.sin x]-[{1/(1+cos x)}.(-sin x)]
=> {sin x/(1-cos x)} + {sin x/(1+cos x)}
=> (sin x+sinx)/sin^2 x……..solving (1-cosx) and (1+cos x) in denominator we get sin^2 x.
=> 2sin x/ sin^2 x
=>2/ sin x
Reciprocal of sinx is cosec x.
=>2 cosec x (Hence proved)
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