Question

if y = 2 secx -6 tanx+5√x+2 then find dy/ dx ​

Answer 1

y=log(secx+tanx)

dx

dy

=

secx+tanx

1

(secx+tanx)

′

=

secx+tanx

1

(secxtanx+sec

2

x)

=

secx+tanx

1

secx(tanx+ secx)=secx

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Answer 2

Answer:

ye = √ ( tanx) y^2y dydx = sec^2x dydx = sec^2×2y = sec^2×2y tanx