If y = 2/sin thetta + root 3 cos thetta, then the minimum value of y is
(A) 1
(B) 2
(C) 1/root 3 + 1
(D) 1/2
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Answer:
B) 2
Explanation:
sin thetta is in denominator takes it maxm value that is 1
cos thetta is in numerator take its minm value that is o
putting in equation
(2/1) + root 3 ×0 = 2
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