Question

If y=2/sin0+v3cos0
then the minimum value of y is

1) 1. 2)2. 3)1/v3+1. 4)1/2​

Answer 1

Explanation:

minimum value =✓a^2-b^2

=✓2^2-✓3^2=4-3=1

option 1 is correct

asinA +bcosA. then min value =✓a^2-b^2