If
y = 2e" sinx
then
dy
dan
is
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Step-by-step explanation:
Steps:
ddx(x2exsin(x))
Apply the power rule: (f⋅g)′=f′⋅g+f⋅g′f=x2,g=exsin(x)
=ddx(x2)exsin(x)+ddx(exsin(x))x2
Solving for ddx(x2):
Apply the power rule: ddx(xa)=a⋅xa−1
=2x2−1→=2x
Solving for ddx(exsin(x))
Apply the power rule: (f⋅g)′=f′⋅g+f⋅g′f=x2,g=exsin(x)
=ddx(ex)sin(x)+ddx(sin(x))ex
Solving for ddx(ex)
Apply the common derivative: ddx(ex)=ex
=ex
Solving for ddx(sin(x))
Apply the common derivative: ddx(sin(x))=cos(x)
=cos(x)
Plugging in all solved derivatives:
ddx(x2)exsin(x)+ddx(exsin(x))x2=2xexsin(x)+exx2sin(x)+cos(x)x2ex
Rearrange and simplify:
=x2exsin(x)+2xexsin(x)+x2excos(x)=xex((x+2)sin(x)+xcos(x))
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