If y +2kX+k+1=0 and x + (k + 2)x+2k-1 = 0
has exactly one root common, then the value of k is
(1) -2
(2) 2
(3) 2/3
(4) -2/3
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if y+2kx+k+1=0and x+(k+2)x+2k-1=0,then answer is-2/3
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