Question

If y= 2sin²θ + tanθ then dy/dθ will be-​

Answer 1

Answer:

$4 \sin( \theta) \cos( \theta) + { \sec( \theta) }^{2}$

Explanation:

$y = 2 { \sin( \theta) }^{2} + \tan( \theta) \\ \\ \frac{dy}{d \theta} = \frac{d}{d \theta} (2 { \sin( \theta) }^{2} + \tan( \theta) ) \\ \\ \frac{dy}{d \theta} = 2 \frac{d}{d \theta} { \sin( \theta) }^{2} + \frac{d}{d \theta} \tan( \theta) \\ \\ \frac{dy}{d \theta} = 4 \sin( \theta) \cos( \theta) + { \sec( \theta) }^{2}$