if y=2sin3x then find dY/dX
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Answered by
2
dy/dx = 2d(sin3x)/dx • d(3x)/dx
= 2cos3x• 3
= 6cos3x
= 2cos3x• 3
= 6cos3x
Answered by
0
Answer:
dx2=d2
Xx3=3x
Explanation:
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