Question

if y=2x^3/3+x+7 find dy/dx curve at point [0,3]​

Answer 1

Answer:

0

Explanation:

Given, y = 2x^3/3+x+7 = 2x^3/x+10

differentiating both sides by 'x'

we get, dy/dx = d(2x^3/x+10)/dx

by using u/v or division rule

differentiation (u/v) = (u' v - v' u)/v^2

= [(6x^2)(x+10) - (2x^3)]/(x+10)^2

= (4x^3+60x^2)/(x+10)^2

•°• (dy/dx) at point [0,3] is = [4(0)^3+60(0)^2]/(0+10)^2

= 0/10^2 = 0