Physics, asked by vinayakmandal99, 1 year ago

if y = 2x^3 – 8x^2 + 8x, then the minimum value of y will exist at x is equal to

Answers

Answered by Kundank
1
the above expression can be written as
2x {(x - 2)}^{2}
let x = -b

we need negative value to get minimum value of y

but as we can see as "b" increase the value of "Y" decreases

so we cannot find any particular value of b for which Y is minimum
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