Question

If y= 2x is a chord of the circle x^2+y^2-10x=0 find the eq of circle with this chord as diameter​

Answer 1

HERE IS YOUR ANSWER MATE

We are given that y=2x

Therefore, putting the value of y in the given equation we have,

x^2+(2x)^2-10x=0

x^2+4x^2-10x=0

5x^2-10x=0

if you want the value of you can take 5x common then you get the value of x is x=2 and x=0

HOPE IT HELPS YOU

PLZZZ MARK BRAINLIEST

THANK YOU