Question

If y = 3^1/3+3, then y^3 - 9y^2 + 27 y =​

Answer 1

$y = \sqrt[3]{3} + 3$

${y}^{3} = 3 + {3}^{3} + 3 \sqrt[3]{3} (3)(3 + \sqrt[3]{3} )$

${y}^{3} = 30 + 9\sqrt[3]{3} y$

${y}^{3} - 9y( \sqrt[3]{3} + 3 - 3) = 30$

${y}^{3} - 9y(y - 3) = 30$

${y}^{3} - 9 {y}^{2} + 27y = 30$