Question

If y= 3^1/logx^9
, .x is​

Answer 1

Answer:

write your question properly

Answer 2

Answer:

The value of X is $x=y^{2}$

Step-by-step explanation:

$y=3^{\wedge} \log (-1) \times 9$

$\log 3 y=\log 3,3^{*} \log { }^{\wedge}(-1) \times 9$

$\log ^{\wedge}(-1) 3 y=\log x 9$

$\log 3 y=\log 9 x$

$x=y^{\wedge} 2$

The logarithm stands for the inverse function to exponentiation. That represents the logarithm of a given number x stands as the exponent to which another fixed number, the base b, must be submitted, to produce that numeral x.

A logarithm exists as a power to which a numeral must be raised to obtain some other number. For example, the base ten logarithms of 100 exist 2, because ten presented to the power of two is 100: log 100 = 2.

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