Question

If y^3– 3y + 2x = 0 Find its differential w.r.t"x''​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\tt{y^3-3y+2x=0}$

$\sf{\implies\,3y^2\,\dfrac{dy}{dx}-3\dfrac{dy}{dx}+2=0}$

$\sf{\implies\,3(y^2-1)\,\dfrac{dy}{dx}+2=0}$

$\sf{\implies\,3(y^2-1)\,\dfrac{dy}{dx}=-2}$

$\sf{\implies\,\dfrac{dy}{dx}=\dfrac{-2}{3(y^2-1)}}$

$\sf{\implies\,\dfrac{dy}{dx}=\dfrac{2}{3(1-y^2)}}$