If y – 3 and y + 3 are the factors of 4y3 + ay2 + by, then (a – b) is equal to
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Step-by-step explanation:
for finding zero
y -3=0
y = 3
p(y) = 4y3 +ay2 + by
p(3)= 4 ×3 ×3 + a ×3×2 + b×3
= 36+6a+b3
for finding zero
y+3=0
y= -3
p(y)= 4y3+ ay2 +by
p(-3) = 4×-3×3 +a ×-3 ×2+b× -3
= -36-6a -3b
36+6a +b3 = -36-6a-3b
it's incomplete but I think someone can help
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