Math, asked by shimply6388, 19 days ago

If (y-3) is a factor of y^-2y^-9y+18then find the other two factors

Answers

Answered by bagkakali
0

Answer:

y^3-2y^2-9y+18

=y^2(y-2)-9(y-2)

=(y-2)(y^2-9(

=(y-2){(y)^2-(3)^2}

=(y-2)(y+3)(y-3)

so, if one factor is (y-3) then the other two factors are (y+3) and (y-2)

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