If y-3 is a factor of y^3-2y^2-9y+18
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Hello Dear!!!
Here's your answer....
Given,
p(x) = y^3-2y^2-9y+18
Zero of y-3 is
y - 3 =0
y = 3
Substitution
y^3-2y^2-9y+18
(3)^3 - 2(3)^2 -9(3) + 18
27-2(9)-27+18
27-27+18-18
0
It is the factor...
y - 3 is the factor of p(x)
_______________________
Hope this helps you....
Here's your answer....
Given,
p(x) = y^3-2y^2-9y+18
Zero of y-3 is
y - 3 =0
y = 3
Substitution
y^3-2y^2-9y+18
(3)^3 - 2(3)^2 -9(3) + 18
27-2(9)-27+18
27-27+18-18
0
It is the factor...
y - 3 is the factor of p(x)
_______________________
Hope this helps you....
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