Question

if y-3 is a factor of y³- ky² + (k+1) y-12 , find the value of 'k'​

Answer 1

Answer:

The value of K = 0.

Step-by-step explanation:

y-3= 0

then , y = 3

Replace y with 3 in given equation,

y^3 - ky^2 + ( k+1 ) y - 12 = 0

we get,

(3)^2 - k(3)^2 + (k+1)3 - 12 = 0

9 - 9k + 3k + 3 - 12 = 0

-9k + 3k + 3 - 12 + 9 = 0

-6k = 0

k = 0.