If (y-3) is factor of y³-2y²-9y+18 then find the other two factors. can any one
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Answer:
→y³-3y²+y²-3y-6y+18 =0 ⇒>
→y²(y-3)+y(y-3)-6(y-3) =0
=> (y-3)(y² +y-6)= 0
→(y-3)(y²+3y-2y-6)=0
(y-3)(y+3)(y-2)=0
(y+3) and (y-2). (Answer)
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answer refers to attachment..!!!
both of attachment is correct...
thank you for your thanks...!!
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