Question

If y=3 is one root of the quadratic equation ky2-10y+3=0 find the value of k?( y2 read as 'y square')​

Answer 1

Answer:

3

Step-by-step explanation:

If 3 is a root of the given equation, LHS must be 0. If such:

⇒ ky^2 - 10y + 3 = 0

⇒ k(3)^2 - 10(3) + 3  = 0

⇒ k(9) - 30 + 3 = 0

⇒ 9k - 27 = 0

⇒ 9k = 27

⇒ k = 27/9

⇒ k = 3

           y^2 is y².

Answer 2

Answer:

• y = 3 is one root of Equation
• Equation : ky² - 10y + 3 = 0

• According to the Question :

⇒ ky² - 10y + 3 = 0

• Putting value of y

⇒ k(3)³ - 10(3) + 3 = 0

⇒ (k × 9) - 30 + 3 = 0

⇒ 9k - 27 = 0

⇒ 9k = 27

• Dividing both term by 9

⇒ k = 3

∴ Hence, the value of k is 3.