Question

if (y-3) is the factor of y³-2y²-9y+18 then the find the other two. factors.​

Answer 1

Answer:

Step-by-step explanation:

Given  

if (y-3) is the factor of y³-2 y²-9 y+18 then the find the other two. factors.

 Now given equation will be

       Y^3 – 2y^2 – 9y + 18 = 0

   Grouping we get the factors as

Y^2(y – 2) – 9(y – 2)

 (y – 2)(y^2 – 9)

 (y – 2)(y^2 – 3^2)

 (y – 2)(y + 3)(y – 3) (because a^2 – b^2 = (a + b)(a – b))

So the other two factors are (y – 2)(y + 3)

Answer 2

Step-by-step explanation:Given,if (y-3) is the factor of y³-2y²-9y+18 then find the other two.now the equation will be= y³-2y²-9y+18=0Now we get factors as y²(y-2)-9(y-2)(y-2)(y²-3²)(y-2)(y+3)(y-3) beacause a²-b²=(a+b)(a-b)so the other two factors are(y-2) ( y+3)